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1)  overlong welded seam
超长焊缝
2)  the length of weld
焊缝长度
1.
The accurate determination of the length of welds in tubular joint is the basis of the calculation of the strength of welds.
连接焊缝长度的准确计算是钢管相贯节点焊缝承载力计算的基础。
3)  over-dimensioned-slot-less
超长无缝
4)  ultrasonic seam welding
超声波缝焊
1.
The mechanism of ultrasonic seam welding of copper plates and tubes for collecting solar energy was investigated.
研究了太阳能集热铜片和铜管的超声波缝焊机理 。
5)  capability of depositing a long small bead
一根焊条可焊的焊缝长
6)  ultrasonic inspection for weld seam
焊缝超声波探伤
1.
: The objective of this article is to discuss the main deference between JB4730-94 and ASME code on the respect of ultrasonic inspection for weld seam
本文讨论了JB4730-94标准与ASME规范在焊缝超声波探伤方面的主要差别。
补充资料:ANSYS工字梁焊缝初应力例子

建立好模型
…..
/SOLU
!*
ANTYPE,0
/INPUT,'input','txt',
/INPUT,'output1','txt',
!*
ISFILE,READ,1,txt, ,0
SOLVE
=====================
!定义残余应力矩阵
I=1
fy=310e6
!定义单元中心坐标数组,初应力数组
*DIM,EleCenter,ARRAY,NumNode,3,1, , ,
*DIM,EleIS,ARRAY,NumNode,1,1, , ,
*DO,I, 1, NumNode,1
!得到单元中心坐标
*GET,EleCenter(I,1,1),ELEM,I,CENT,X
*GET,EleCenter(I,2,1),ELEM,I,CENT,Y
*GET,EleCenter(I,3,1),ELEM,I,CENT,Z
!焊缝位置在X=1.0 到1.05 之间
*IF,EleCenter(I,1,1),GT,1,THEN
*IF,EleCenter(I,1,1),LT,1.05,THEN
*IF,EleCenter(I,2,1),GT,0.5,THEN
!上翼缘初始应力
EleIS(I,1,1)=-20*fy*EleCenter(I,3,1)**2+0.3*fy
*endif
*IF,EleCenter(I,2,1),LT,0.0,THEN
!下翼缘初始应力
EleIS(I,1,1)=-20*fy*EleCenter(I,3,1)**2+0.3*fy
*endif
!腹板初始应力
*if,EleCenter(I,2,1),GE,0.0,THEN
*IF,ELECENTER(I,2,1),LE,0.5,THEN
EleIS(I,1,1)=4.076*fy*(EleCenter(I,2,1)-0.5)**2
EleIS(I,1,1)=EleIS(I,1,1)-0.719*fy
*IF,EleIS(I,1,1),LT,-0.3*fy,THEN
ELeIS(I,1,1)=-0.3*fy
*ENDIF


*ENDIF
*ENDIF
*ENDIF
*ENDIF
*ENDDO
===============
!输出应力数值
*CFOPEN,'1','txt',' '
*DO,I,1,3840
!*IF,EleIS(I,1,1),ne,0.,then
*VWRITE,'!'
(A)
*VWRITE,'! Stress for element',
(A,F)
*VWRITE,'!'
(A)
*VWRITE,'eis,',I
(A,F)
P=EleIS(I,1,1)
*VWRITE,P,0.,0.,0.,0.,0.
(E,E,E,E,E,E)
!*ENDIF
*ENDDO
*CFCLOS

说明:补充资料仅用于学习参考,请勿用于其它任何用途。
参考词条